(t+4)(t+2)+1因式分解怎么算

2025-12-25 07:00:28
推荐回答(1个)
回答1:

(t+4)(t+2)+1
=t的2次方+6t+8+1
=t的2次方+6t+9
=(t+3)的2次方

(t+4)(t+2)+1
=[(t+2)+2](t+2)+1
=(t+2)的2次方+2(t+2)+1
=[(t+2)+1]的2次方
=(t+3)的2次方