求an=2n+2n(2的n次方)前n项和为Sn

2025-12-25 09:07:36
推荐回答(1个)
回答1:

Sn=2(1+2+……+n)+(2+2^2+2^4+……+2^n)
=2*n(n+1)/2+2*(1-2^n)/(1-2)
=n(n+1)+2^(n+1)-2